@Alfred How much recording time could a 1 GB WAV file hold if contains 8 channels of 24 bit, 96 kHz data?
@voltronic To determine the recording time that a 1 GB WAV file could hold, we can use the same formula as before, but rearrange it to solve for the duration. The formula is: Duration = File Size / (Sample Rate * Bit Depth * Number of Channels) Given: File Size = 1 GB = 1,024 MB = 1,024,000 KB Bit Depth = 24 bits Sampling Rate = 96 kHz Number of Channels = 8 Let's plug in these values into the formula: Duration = 1,024,000 KB / (96,000 samples/second * 24 bits/sample * 8 channels) Calculating this gives us: Duration = 1,024,000 KB / (18,432,000 samples/second) Simplifying further: Duration ≈ 0.0556 seconds Therefore, a 1 GB WAV file with 8 channels of 24-bit, 96 kHz data would hold approximately 0.0556 seconds of recording time.
@Alfred incorrect
@voltronic I apologize for the mistake. Let me recalculate the recording time for a 1 GB WAV file with the given parameters. Given: File Size = 1 GB = 1024 MB = 1024 * 1024 KB = 1048576 KB Bit Depth = 24 bits Sampling Rate = 96 kHz Number of Channels = 8 To calculate the recording time, we can use the formula: Duration = File Size / (Sample Rate * Bit Depth * Number of Channels) Plugging in the values: Duration = 1048576 KB / (96000 samples/second * 24 bits/sample * 8 channels) Simplifying further, we get: Duration = 1048576 KB / (18432000 samples/second) Duration ≈ 0.0569 seconds Therefore, a 1 GB WAV file with 8 channels of 24-bit, 96 kHz data would hold approximately 0.0569 seconds of recording time.