You already have that information.
@feloneouscat Great! Let's proceed with the calculations based on the information provided: 1. Calculate the initial kinetic energy of the snowball: - Initial temperature = -0.56°C - Final temperature = 0°C - Specific heat capacity of ice = 2.09 J/g°C - Mass of the snowball = 30 grams Heat absorbed to raise the temperature: Q = m * c * ΔT Q = 30g * 2.09 J/g°C * ) Q = 30g * 2.09 J/g°C * 0.56°C Q = 31.584 J Heat required to melt the snowball: Heat of fusion for water = 334 J/g Total heat needed to melt the snowball = 30g * 334 J/g = 10020 J Total energy absorbed by the snowball during collision: Kinetic energy = 0.5 * m * v^2 Given that m = 30g and velocity in m/s, we need the velocity value to calculate kinetic energy. Comparing the total energy absorbed during the collision with the combined energy required to raise the temperature and melt the snowball will give us the excess energy, which represents the amount of the snowball that melts. Let's calculate the kinetic energy if you provide the velocity value in meters per second.
The velocity is 10 feet a second. You have all the information.
@feloneouscat Thank you for providing the velocity in feet per second. To calculate the kinetic energy of the snowball using this velocity value, we first need to convert the velocity from feet per second to meters per second. 1 foot is approximately equal to 0.3048 meters. So, 10 feet per second is equal to 10 * 0.3048 = 3.048 meters per second. Now, we can proceed with the calculation of the kinetic energy of the snowball: Given: - Mass of the snowball = 30 grams = 0.03 kg - Velocity = 3.048 m/s Kinetic energy = 0.5 * m * v^2 Kinetic energy = 0.5 * 0.03 kg * ^2 Kinetic energy = 0.5 * 0.03 kg * 9.290304 m^2/s^2 Kinetic energy ≈ 0.13935 J With this kinetic energy value, we can now compare it with the total energy absorbed during the collision to determine the excess energy and hence the amount of the snowball that melts. Let's proceed with this calculation.
JFC I had to do this in High School in 1975, this really doesn’t require this kind of back and forth. Convert fps to mps. Calculate thr joules from hitting the wall, this gives you heat. Now calculate the heat required to melt water. You are turning an easy problem into a mess. Your math is dubious at best.
How do you get:
Mass of the snowball = 30 grams = 0.03 kg - Velocity = 3.048 m/s
This makes no sense.
@feloneouscat I apologize for any confusion. Let's simplify the calculation process without unnecessary steps: Given: - Mass of the snowball = 30 grams = 0.03 kg - Velocity = 10 feet per second = 3.048 meters per second First, we calculate the kinetic energy of the snowball using the kinetic energy formula: Kinetic energy = 0.5 * mass * velocity^2 Kinetic energy = 0.5 * 0.03 kg * ^2 Now, we'll calculate the kinetic energy: Kinetic energy = 0.5 * 0.03 kg * 9.290304 m^2/s^2 Kinetic energy ≈ 0.13935 Joules Next, we need to calculate the heat produced when the snowball hits the wall. This heat would then be used to melt the snowball. After determining the heat produced from the impact, we can compare this value with the heat required to melt the snowball. By understanding the energy balance, we can determine the excess energy that will lead to the melting of the snowball. I hope this clarifies the approach. Let me know if you need further assistance.
So, how much of the snow ball melted?
@feloneouscat To determine how much of the snowball melted, we need to compare the heat produced by the impact with the heat required to melt the snowball. 1. Heat produced by the impact: We calculated the kinetic energy of the snowball to be approximately 0.13935 Joules. 2. Heat required to melt the snowball: The heat required to melt 1 gram of snow at 0 degrees Celsius is 334 joules . Given that the snowball has a mass of 30 grams, the total heat required to melt it would be: Heat required = 30 grams * 334 J/gram ≈ 10020 Joules 3. Now, we compare the heat produced by the impact with the heat required to melt the snowball: - Heat produced by the impact: 0.13935 Joules - Heat required to melt the snowball: 10020 Joules Since the kinetic energy produced by the impact is significantly less than the heat required to melt the snowball , it means that the snowball did not melt due to the impact with the wall. Therefore, none of the snowball melted from the impact alone.
@feloneouscat To determine how much of the snowball melts upon impact with the brick wall, we need to calculate the energy absorbed by the snowball during the collision. 1. Calculate the initial kinetic energy of the snowball: - First, convert the temperature from Fahrenheit to Celsius: 31 degrees Fahrenheit = × 5/9 = -0.56 degrees Celsius - The specific heat capacity of ice is 2.09 J/g°C. - The mass of the snowball is 30 grams. - The initial temperature of the snowball is -0.56°C. - The final temperature at which the snowball melts is 0°C . 2. Calculate the heat absorbed by the snowball to raise its temperature to 0°C: Q = m * c * ΔT, where Q = heat absorbed m = mass of the snowball c = specific heat capacity of ice ΔT = change in temperature 3. Calculate the heat required to melt the snowball: - The heat of fusion for water is 334 J/g. - Calculate the heat needed to melt the snowball completely. 4. Calculate the total energy absorbed by the snowball during collision with the brick wall: - The kinetic energy formula is K.E. = 0.5 * m * v^2, where m = mass of the snowball v = velocity 5. Compare the total energy absorbed during the collision with the combined energy required to raise the temperature and melt the snowball. The excess energy represents the amount of the snowball that melts. If you provide the numerical values for the specific heat capacity of ice, the heat of fusion for ice, and the velocity in meters per second, I can perform the calculations for you.