@Knitpurrl
Eh?
Zero was not given as an option.
Odd stuff.
@Knitpurrl
LOL
You have to break a rule solve it no matter
@Knitpurrl @Xponent_Rob In that case, 13 in box 1, 13 in box 2 and 5-1 in box 3 would do the trick.
@peterquirk @Xponent_Rob
👏👏👏👏👏🤓👏👏👏👏
@Xponent_Rob I think the answer is that the “rules” are not specific on what you can put in a box or if you have to use all the boxes… it’s a think outside the ‘box’ problem.
@Xponent_Rob Or…. 2 numbers in one box 13, 13 in one box +3 +1.